CodeChargeMVP
Posts: 473
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| Posted: 06/20/2011, 3:40 AM |
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Hi,
On the after file process I�m catching the size of an image this way:
$ImagenJPG = imagecreatefromjpeg("../template/images/justificantes/".$NombreArchivoNuevo);
$justgasto->H_AnchuraImagen->Value = imagesx($ImagenJPG);
$justgasto->H_AlturaImagen->Value = imagesy($ImagenJPG);
Than I catch the image height and weight and put into a hidden object, to
do some manipulations with this parameters but when checking the values of
the hidden buttons on the client side this way:
var AnchuraImagen = document.forms[0].elements["H_AnchuraImagen"].value;
var AlturaImagen = document.forms[0].elements["H_AlturaImagen"].value;
alert(AnchuraImagen);
alert(AlturaImagen);
the variables return nothing, no values on the hidden objects.
I know for sure than on the PHP Side the image exists, and than the fuctions returns some values, i don�t know why I can�t access to them later on the client side.
�Any suggestion?
Thank you very much in advance.
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CodeChargeMVP
Posts: 473
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| Posted: 06/20/2011, 4:03 AM |
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Hi,
I think this is not possible to resolve that way, when the user saves the file
on the after file process, yes I can access to height and weight but I´ve release
than after that I should click on save button form by update it so the values on
the hidden object obviously gone so I can´t handle them.
I think this also would solved with an ajax solution.
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Entrepeneur | NT Consultant
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jjrjr2
Posts: 131
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| Posted: 06/20/2011, 8:05 AM |
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Hi
Could you be a little more clear as to what You are wanting to do???
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John Real - More CodeCharge Studio Support at - http://CCSElite.com
Real Web Development At: http://RealWebDevelopment.us |
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CodeChargeMVP
Posts: 473
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| Posted: 06/21/2011, 2:05 AM |
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Hi,
I think the issue gotta be resolved using the event "before show" of the FileUpload componenent,but I´ve a question about it:
on the before show event i´m doing this:
$ImagenJPG = imagecreatefromjpeg("../template/images/justificantes/"."imagen.jpg");
$justgasto->H_AnchuraImagen->Value = imagesx($ImagenJPG);
$justgasto->H_AlturaImagen->Value = imagesy($ImagenJPG);
This works out, but I need a php sentence which return me the filename of the file on the FileUpload component, than I´ll change "imagen.jpg" for that sentence.
¿Do you know how get the filename with a php sentence?
Thank you very much in advance.
Quote jjrjr2:
Hi
Could you be a little more clear as to what You are wanting to do???
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Entrepeneur | NT Consultant
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jjrjr2
Posts: 131
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| Posted: 06/21/2011, 6:43 AM |
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As you know the filename in the file upload component is the actual filename CCS used to upload the file..
The upload component uploads the file & adds a time stamp to it.. Sooo... the file actually uploaded is like so
timestamp.originaluploadname.ext
That is also what is placed into the database for the file name
To get back the original filename you do it like so.
$OriginalFileName=CCGetOriginalFileName($Container->YourFileUploadComponentName->GetValue());
Hope that helps for what U R trying to do..
John
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John Real - More CodeCharge Studio Support at - http://CCSElite.com
Real Web Development At: http://RealWebDevelopment.us |
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CodeChargeMVP
Posts: 473
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| Posted: 06/22/2011, 3:30 AM |
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Hi John,
Thank you very much for your help,
I catched the file name with $nameoftheform->$nameofthefileupload->getfilename();
than everything came on a flash.
The timestamp issue wasn´t a problem.
Now is solved.
Quote jjrjr2:
As you know the filename in the file upload component is the actual filename CCS used to upload the file..
The upload component uploads the file & adds a time stamp to it.. Sooo... the file actually uploaded is like so
timestamp.originaluploadname.ext
That is also what is placed into the database for the file name
To get back the original filename you do it like so.
$OriginalFileName=CCGetOriginalFileName($Container->YourFileUploadComponentName->GetValue());
Hope that helps for what U R trying to do..
John
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Entrepeneur | NT Consultant
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