GRose
Posts: 5
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| Posted: 03/14/2005, 7:38 AM |
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The learning curve on this product is steep and the docmentation is so poor as to be allmost unusable.
Im trying what should be a simple operation yet it is turning into a complete project stopper. If there is a 'workflow' behind the forms built etc it should be clearly documented so a person can reference it .
Im simply trying to build a form where the user clicks on a link and either a or b happens when the user logs in.
a) if the sessionid("EmplDirGroupId") = 1 then
display form EmplDetails with users details for editing
In the before empDetails_beforeShow event disable the fields emp_login, emp_level,emp_picture by setting each fields readonly, disabled property to true. Yet every method of trying to reference these controls gives an "object does not support this properties error."
b) if the sessionid("EmplDirGroupId") = 2 then
display adminMenu Instead
however what should be simple once again appears to be hard because of a lack of clear documentation.
in the onclick event of do_login what should be a simple case of if the sessionid("EmplDirGroupId") = 1 then
redirect="Empdetails.Asp"
else
redirect="Empdetails.Asp"
end if
* allso clearing the return page field on the property tab
dosnt appear to function as it should.
I'm
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GRose
Posts: 5
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| Posted: 03/14/2005, 8:01 AM |
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My apologies for the typo in in part b) it should have read
in the onclick event of do_login what should be a simple case of if the sessionid("EmplDirGroupId") = 1 then
redirect="Empdetails.Asp"
else
redirect="AdminMenu.Asp"
end if
Finally in addition, regardless of what is said elewgere in the forums this product does need a debugger because the number of error 500's you get when trying work things out means you spend more time trying to work out the program flow of the model than you do your own code.
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smalloy
Posts: 107
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| Posted: 03/14/2005, 8:56 AM |
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I had the same need and used this to redirect based on user login:
Dim intGroup
intGroup = CCGetGroupID()
SELECT CASE intGroup
Case 2
redirect = "AdminMenu.asp"
Case 3
redirect = "Emp_Initial.asp"
Case 6 'Paterson
redirect = "/PatersonReport/PatersonReportForm.asp"
Case Else
redirect = "Emp_Initial.asp"
End Select
Login_DoLogin_OnClick = True
End If
End With
'End Login
You can easily use CCGetUserID() or Session("userID") instead of CCGetGroupID().
Also, the Debugging issue is not an issue with the application but rather with the language. There are several ways to debug with ASP, the easiest is to write a Response.Write (your variable or "anytext in quotes") This will show at the top of your page, if it doesn't you'll need a Resoponse.End to stop the rest of your code overwriting your Response.Write.
If your in a MS environment there are utilities for both Server and Client side debugging, here are some good articles to read:
http://www.microsoft.com/technet/prodtechnol/windows200.../tips/t100.mspx
http://msdn.microsoft.com/library/default.asp?url=/libr...sinasppages.asp
Good luck!
_________________
Anything can be done, just give me time and money. |
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peterr
Posts: 5971
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| Posted: 03/14/2005, 10:59 AM |
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GRose,
I can add that a debugger is very far on the list of user requests/wishes that we are receiving. You can add your requests to the Wishes forum or to our support if you like your wish to be counted. If most of the other users agree then we'll look into that.
However, receiving errors 500 probably cannot be a sufficient reason for implementing a debugger since ASP already provides sufficient debugging information to resolve most such problems. If you're receiving errors 500 then possibly you should start with configuring your Web browser not to display those but to give you full debug information. See http://forums.codecharge.com/posts.php?post_id=51140
_________________
Peter R.
YesSoftware Forums Moderator
For product support please visit http://support.yessoftware.com |
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